[apgw]

Following the steps to generate the mapping to the BONUS table, I get a similar error to an earlier posting (12/12/04, “Hibernate Tutorial Question – SQL String?”). This is connecting to an Oracle db:

“The content of element type “class” must match … line 17″
and
“The serializable class Bonus does not declare a static final serialVersionUID field of type long …line 13″

I am using Eclipse 3.1.1, with the MyEclipse hibernate 4.0.1

The Bonus.hbm.xml:

<?xml version=”1.0” encoding=’UTF-8′?>
<!DOCTYPE hibernate-mapping PUBLIC
“-//Hibernate/Hibernate Mapping DTD 3.0//EN”
“http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd&#8221; >

<!– DO NOT EDIT: This is a generated file that is synchronized –>
<!– by MyEclipse Hibernate tool integration. –>
<!– Created Sat Nov 19 17:29:22 PST 2005 –>
<hibernate-mapping package=”com.genuitec.hibernate”>

<class name=”Bonus” table=”BONUS”>

<property name=”ename” column=”ENAME” type=”string” />
<property name=”job” column=”JOB” type=”string” />
<property name=”sal” column=”SAL” type=”long” />
<property name=”comm” column=”COMM” type=”long” />
</class>

</hibernate-mapping>

How and where would I fix this?

[Riyad Kalla]

“The content of element type “class” must match … line 17″

The problem is that the table you mapped, BONUS, does not have a primary key defined. So your <class> element is generated without an ID which is required for Hibernate to persist instances of that class.

“The serializable class Bonus does not declare a static final serialVersionUID field of type long …line 13”

This is a Java compiler warning you can change under your compiler settings from Java preferences.

[apgw]

Thanks for the help.

[Author]

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